The JavaScript Math.abs() method
The Math.abs() method returns the absolute value of a number — its magnitude with any negative sign removed. Math.abs(-7) is 7, and Math.abs(7) is also 7. It's the standard way to get the distance between two values regardless of which is larger.
Overview
Math.abs() strips the sign off a number, giving you its distance from zero. -7 and 7 both become 7. It's a small method with one clear job, and it shows up whenever direction doesn't matter but magnitude does.
The everyday use is finding how far apart two numbers are without worrying which one is bigger: Math.abs(a - b) gives the difference as a positive number every time. That's the basis of distance checks, tolerance comparisons ("are these within 0.01 of each other?") and progress measurements.
It returns NaN for values that can't be converted to a number, and works fine on numeric strings via coercion. For a quick visual: Math.abs(-3.5) is 3.5 — it keeps the decimals, it only drops the sign.
Syntax
Math.abs(-7) // 7
Math.abs(7) // 7
Math.abs(a - b) // distance between a and b
Parameters
The Math.abs() method accepts the following parameters.
| Parameter | Description |
|---|---|
x |
The number whose absolute (non-negative) value you want. |
Example
<pre id="out" style="font:15px ui-monospace,monospace"></pre>
<script>
const target = 100, guess = 87;
const off = Math.abs(target - guess);
document.getElementById('out').textContent =
'You were off by ' + off; // You were off by 13
</script>
Best practices
- Use
Math.abs(a - b)to get the difference between two numbers as a positive value. - Combine it with a small threshold for "close enough" floating-point comparisons.
- It only removes the sign — decimals are preserved.
- Non-numeric input returns
NaN, so validate values you don't control.
Frequently asked questions
What does Math.abs() do?
How do I get the difference between two numbers?
Math.abs(a - b), which gives a positive result no matter which number is larger.Does Math.abs() round the number?
How do I compare two floats for near-equality?
Math.abs(a - b) < 0.0001.